一道因式分解题,帮帮忙,谢谢

x(x+1)(x-1)+xy(x-y)-y(y+1)(y-1)
=x(x^2-1)+xy(x-y)-y(y^2-1)
=x^3-x+xy(x-y)-y^3+y;
=x^3-y^3-(x-y)+xy(x-y)
=(x-y)(x^2+xy+y^2)-(x-y)+xy(x-y)
=(x-y)(x^2+xy+xy+y^2-1)
=(x-y)((x+y)^2-1)
=(x-y)(x+y-1)(x+y+1)

x(x+1)(x-1)+xy(x-y)-y(y+1)(y-1)
＝x(x+1)(x-1)+xy(x＋1-1-y)-y(y+1)(y-1)
=x(x+1)(x-1)+xy(x＋1）—xy(y＋1)-y(y+1)(y-1)
=x(x+1)(x-1+y)-y(y+1)(x+y-1)
=(x2+x-y2-y)(x+y-1)
=(x-y)(x+y+1)(x+y-1)

=x(x+1)(x-1)+xy[(x-1)-(y-1)]-y(y+1)(y-1)
=[x(x+1)+xy](x-1)-[y(y+1)+xy](y-1)
=x(x+1+y)(x-1)-y(y+1+x)(y-1)
=(1+x+y)(x^2-x-y^2+y)
=(1+x+y)(x-y)(x+y-1)

很容易！
^3表示3次方
^2表示平方
x(x+1)(x-1)+xy(x-y)-y(y+1)(y-1)
=x^3-x+xy(x-y)-y^3+y
=x^3-y^3-(x-y)+xy(x-y)
=(x-y)(x^2+xy+y^2)-(x-y)+xy(x-y)
=(x-y)(x^2+xy+y^2-1+xy)
=(x-y)((x+y)^2-1)
=(x-y)(x+y-1)(x+y+1)

呵呵，多记记公式就会的！

x(x+1)(x-1)+xy(x-y)-y(y+1)(y-1)
=x^3-x+xy(x-y)-y^3+y
=x^3-y^3-(x-y)+xy(x-y)
=(x-y)(