X的平方－2X＝2，求X

来源：百度知道 编辑：UC知道 时间：2024/05/10 06:52:14
再求(X-1)的平方+(X+3)(X-3)+(X-3)(X-1)

X^2－2X＝2
X^2-2X+1=2+1
(X-1)^2=3
X-1=±根号3
X=1±根号3

(X-1)^2+(X+3)(X-3)+(X-3)(X-1)
=x^2 -2x+1+x^2 -9+x^2 -4x+3
=3x^2 -6x-5
=3(x-1)^2 -8
=3*3-8
=1

X^2－2X＝2
X^2-2X+1=2+1
(X-1)^2=3
X-1=±根号3
X=1±根号3
X1=1+根号3
X2=1-根号3

x^2-2x-2=0

x=[-（-2）±√￣（-2）^2-4×1×（-2）]/2×1

x=1±√￣3

x=1±√￣3