若ax的平方y+(b-1)yx的平方=0,则a,b满足的关系____

ax的平方y+(b-1)yx的平方=0
yx的平方(a+b-1)=0
若xy不为0
则a+b=1

A=2^2+3xy-2x-1,B=-x^2+xy-1
3A+6B的值与x无关,则
3A+6B=3*(2^2+3xy-2x-1)+6*(-x^2+xy-1)
=12+9xy-6x-3-6x^2+6xy-6
=3+15xy-6x-6x^2
=3+x(15y-6-6x)
15y-6-6x=0
y=(2/5)*(1+x)

ax^2y+bx^2y-x^2y=0
x^2(a+b-y)=0
a+b=y

3A+6B=3(2x^2+3xy-2x-1)+6(-x^2+xy-1)
=6x^2+9xy-2x-3-6x^2+6xy-6
=15xy-2x-9