y=Sin(π/4-2x)的单调区间?.
来源:百度知道 编辑:UC知道 时间:2024/06/18 16:58:25
帮忙啊.
.速度点..
.速度点..
y=sin(π/4-2x)=sin[π-(π/4-2x)]=sin(2x-3π/4)=sin2(x-3π/8)
y=sin2(x-3π/8)的图象即由y=sinx的图象横坐标缩小一倍,向右平移3π/8个单位得到
y=sinx的单调递增区间(2kπ-π/2,2kπ+π/2),单调递减区间(2kπ+π/2,2kπ+3π/2)
y=sin2x的单调递增区间(kπ-π/4,kπ+π/4),单调递减区间(kπ+π/4,kπ+3π/4)
y=sin2(x-3π/8)的单调递增区间(kπ+π/8,kπ+5π/8),单调递减区间(kπ+5π/8,kπ+9π/8)
即y=sin(π/4-2x)的单调递增区间(kπ+π/8,kπ+5π/8),单调递减区间(kπ+5π/8,kπ+9π/8)
单调减区间[-π/8+kπ,3π/8+kπ]
单调增区间[3π/8+kπ,7π/8+kπ]
单调减{-1/8PI+kPI,3/8PI+kPI}
其余为单调增
kπ+-π/2 减..〔Kπ+π/2,kπ+π]增
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