一道函数题，求解！~帮我呀！很急！

Y1=K1X
y2=k2/x

k1x+k2/x=y

2k1+k2/4=19
3K1+K2/9=19

K1=5 k2=36

y=5x+36/x

设y1=kx，y2=h/x^2,有题意有
19=2k+h/4,
19=3k+h/9，解得
k=5，h=36，所以y与x之间的函数关系式是
y=5x+36/x^2

设y1 = mx y2 = n/x^2
y = mx + n/x^2
当x = 2时
y = 2m + n/4 = 19
当x = 3时
y = 3m + n/9 = 19
解得
m = 5
n = 36
y = 5x + 36/n^2

设y1=ax;y2=b/x^2
代入x=2;y1=2a,y2=b/4 19=2a+b/4
x=3;y1=3a,y2=b/9 19=3a=b/9
a=5,b=36
y=5x+36/x^2

Y1=a/x y2=bx {19=2a+b/2
19=3a+b/3 a=19/5,b=152/5 .y=5x/19+152x/5

假设y1=mx,y2=n/x^2,则
y=mx+n/x^2
分别代x=2,3进去，得
y=2m+n/4=3m+n/9=19
解得：m=5,n=36
所以y=5x+36/x^2