x-(x-1)/2=2-(x+2)/3

来源：百度知道 编辑：UC知道 时间：2024/05/22 13:41:27
要有过程

[x-(x-1)]/2=[2-(x+2)]/3

等式两边同乘6,3[x-(x-1)]=2[2-(x+2)]

3x-3(x-1)=4-2(x+2)

3x-3x+3=4-2x-4

2x=-3,

x=-3/2

左边=x/2+1/2
右边=-x/3+4/3
5x/6=5/6
x=1

x-(x-1)/2=2-(x+2)/3
6X-6(x-1)/2=6*2-6*x+2)/3
6x-3x+3=12-2x-4
x=1

x-1/2x+1/2=2-3x-6;
7/2x=-9/2;
x=-9/7

x-1/2x+1/2=2-1/3x-2/3
移项 得 x-1/2x+1/3x=2-2/3-1/2
合并同类项 得 5/6x=5/6
两边同除以5/6得x=1

x-(x-1)/2=2-(x+2)/3
6X-6(x-1)/2=6*2-6*x+2)/3
6x-3x+3=12-2x-4
x=1