初一数学题(三元一次方程)

来源:百度知道 编辑:UC知道 时间:2024/06/14 08:42:03
若3x+y+2z=28,5x-3y+z=7,求x+y+z

3x+y+2z=28
5x-3y+z=7
10x-6y+2z=14
7x-7y=-14
x-y=-2......-x+y=2
y=x+2

3x+y+2z=3x+x+2+2z=4x+2z+2=28
2x+z=13

-x+y+2x+z=2+13
x+y+z=15 或者...........................................................................................................................................3x+y+2z=28 ①
5x-3y+z=7 ②,求x+y+z
由①得:y=28-3x-2z ③,
代入②得:5x-3(28-3x-2z)+z=7
x=(91-7 z)/14
代入③得:y=28-3(91-7 z)/14-2z
y=(119-7z)/14
x+y=(91-7 z)/14+(119-7z)/14
x+y=15-z
x+y+z=15

3x+y+2z=28
5x-3y+z=7
10x-6y+2z=14
7x-7y=-14
x-y=-2......-x+y=2
y=x+2

3x+y+2z=3x+x+2+2z=4x+2z+2=28
2x+z=13

-x+y+2x+z=2+13
x+y+z=15

3x+y+2z=28 ①
5x-3y+z=7 ②,求x+y+z
由①得:y=28-3x-2z ③,
代入②得:5x-3(28-3x-2z)+z=7
x=(91-7 z)/14
代入③得:y=28-3(91-7 z)/14-2z
y=(119-7z)/14
x+y=(91-7 z)/14+(119-7z)/14
x+y=15-z
x+y+z=15