((x-5)/(x+1))>3
来源:百度知道 编辑:UC知道 时间:2024/05/09 19:14:28
解不等式
解:(X-5)/(X+1)-3>0
(X-5-3X-3)/(X+1)>0
(-2X-8)/(X+1)>0
(X+4)/(X+1)<0
当X+4<0时,X+1>0,X无解
当X+4>0时,X+1<0, -4<X<-1
所以-4<X<-1
移项得X-5>3(X+1)
X不能等于-1
解得不等式为X<-4
解这类的不等式要让一边化为零
((x-5)/(x+1))>3
(x-5)/(x+1)-3>0
(x-5)/(x+1)-9/3>0通分得:
(6x+24)/(3x+3)<0
(6x+24)/(3x+3)<0等价于(6x+24)(3x+3)<0
要使(6x+24)/(3x+3)<0
所以6x+24<0
3x+3>0
或者
6x+24>0
3x+3<0
所以:-4<x<-1
[x+2]/[x+1]-[x+4]/[x+3]-[x+3]/[x+2]+]x+5]/[x+4]
1/x-1 +1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+1/(x-4)(x-5)
已知x*x-5x-2000=0,求((x-2)(x-2)(x-2)-(x-1)(x-1)+1)/x-2的值
(X-1/X)=5,且X<0,求x^10+x^6+x^4+1除以x^10+x^8+x^2+1的值
已知x*x-5x+1=0 求x-1/x=?
(x-4)(x-2)-(x-1)(x+3),其中x=-2/5
f(x)=((5^x)-1)/((5^x)+1)
(5/(X-1)(X+2))+(3/(X+2)(X+3))=2/(X-1)(X-3)
求和:1/[(x+1)(x+2)]+1/[(x+2)(x+3)]+1/[(x+3)(x+4)]+1/[(x+4)(x+5)]
(x+2/x+1)+ (x+6/x+5)=(x+3/x+2)+(x+5/x+4)怎么解?