高中数学题!数学好的快来看啊啊!!

来源:百度知道 编辑:UC知道 时间:2024/05/08 21:15:12
在实数范围内分解因式
4x^2-4x-1
a(a+m)-b(b+m)
x^3(x+y)+y^3(x-y)
a^2+ax-2a-x+1
(x^2+2x+2)(x^2+2x-3)+4
(x+1)(x+2)(x+3)(x+4)+1
(x^2+3x+2)(4x^2+8x+3)-90

4x^2-4x-1=(2x-1+根号2)^2-(2x-1-根号2)

a(a+m)-b(b+m)=(a-b)(a+b+m)

x^3(x+y)+y^3(x-y)=(x+y)[xy+(x^2+y^2)(x-y)]

a^2+ax-2a-x+1=(a-1)(a-1+x)

(x^2+2x+2)(x^2+2x-3)+4=(x+1)^2(x+1-根号3)(x+1+根号3)

(x+1)(x+2)(x+3)(x+4)+1==[(x+1)(x+4)][(x+2)(x+3)]+1
=(x^2+5x+4)(x^2+5x+6)+1
=(x^2+5x+4)(x^2+5x+4)+2(x^2+5x+4)+1
=(x^2+5x+4)^2+2(x^2+5x+4)+1
=(x^2+5x+4+1)^2
=(x^2+5x+5)^2

(x+2)(2x+1)(x+1)(2x+3)-90
=(2x^2+5x+2)(2x^2+5x+3)-90
=(2x^2+5x)^2+5(2x^2+5x)+6-90
=(2x^2+5x)^2+5(2x^2+5x)-84
=(2x^2+5x-7)(2x^2+5x+12)
=(2x+7)(x-1)(2x^2+5x+12)

(x^2+3x+2)(4x^2+8x+3)-90

4x^2-4x-1
=(2x-1+√2)(2x-1-√2)

a(a+m)-b(b+m)
=a^2+am-b^2-bm
=(a+b)(a-b)+m(a-b)
=(a-b)(a+b+m)

x^3(x+y)+y^3(x-y)
=x^4+x^3y+xy^3-y^4
=(x^2+y^2)(x^2-y^2)+xy(x^2+y^2)
=(x^2+xy-y^2)(x^2+y^2)

a^2+ax-2a-x+1
=(a-1)^2+x(a-1)
=(a-1)(a-1+x)

(x^2+2x