1-1/2-1/4-1/8-1/16-1/32-.....-1/512-1/1024-1/2048=?
来源:百度知道 编辑:UC知道 时间:2024/06/08 12:32:58
请把计算公式及过程写清楚。多谢!
1-1/2-1/4-1/8-1/16-1/32-.....-1/512-1/1024-1/2048-1/2048+1/2048
因为1/2048+1/2048=1/1024
1/1024+1/1024=1/512
1/512+1/512=1/256
.......
所以原式=1/2048
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、
原式;1-1/2-1/4-1/8-1/16-1/32-…-1/1024
=1-1-1/2+1/2-1/4+1/4-1/8+1/8-1/16+1/16......-1/1024
【中间的约掉】
=1-1-1/1024
=1/1024
希望能帮到你!!!
1/2048
1后面的所有加起来是2047/2048
1/2048
1-1/2=1/2
1/2-1/4=1/4
.......
急求:A=(1+1/2)(1-1/2)(1+1/3)(1-1/3)(1+1/4)(1-1/4)……(1+1/n)(1-1/n)
(1/x)'=-1/x^2
(1+0.5)(1+1/3)(1+1/4)......(1+1/100)除以(1-1/2)(1-1/3)(1-1/4)......(1-1/100
怎样用简便方法解方程:1/2{1/2[1/2(1/2x-1)-1]-1}=1.???
一道数学题:(1-1/2²)(1-1/3²)(1-1/4²)…(1-1/1999²)(1-1/2000²)
(1/2005-1)(1/2004-1)........(1/3-1)(1/2-1)
(1+1/2)(1+1/3+(1+1/4)……(1+1/100)/(1-1/2)(1-1/3)(1-1/4)……(1-1/100)
1+1/2+1/3+.....+1/n
1+1/2+1/3+...+1/100
1-1/2+1/3-.....-1/10