(1/1-x)-(3/1-x^3)如何通分
来源:百度知道 编辑:UC知道 时间:2024/06/24 08:56:19
1-x^3=(1-x)(1+x+x^2)
前面那项分母分子同时乘以1+x+x^2就行了
1/(1-x)-3/(1-x³)
=(1+x+x²)/[(1-x)(1+x+x²)]-3/[(1-x)(1+x+x²)]
=(1+x+x²)/[(1-x)(1+x+x²)]-3/[(1-x)(1+x+x²)]
=(x²+x-2)/[(1-x)(1+x+x²)]
=[(x+2)(x-1)]/[(1-x)(1+x+x²)]
=-(x+2)/(1+x+x²)
1-x^3
=(1-x)(1+x+x^2)
所以原式:
=((1+x+x^2)-3)/(1-x^3)
=(x^2+x-2)/(1-x^2)
=(x+2)/(x^2+x+1)
(1+x+x^2)/(1-x^3)
-3/(1-x^3)=(x^2+x-2)/(1-x^3)=(x-1)(x+2)/(1-x^3)
=-(x+2)/(1+x+x^2)
已知x*x-3x+1=0,求x*x+1/x*x
若X/X*X+1=1/3,则X*X/X*X*X*X+1=?
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