整式乘除与因式分解的初一题

1. 化简
（1）
(2a+1)(-a-2)+a(2-a)
= (-2a² -5a -2) +(2a -a²)
=-3a²-3a-2

(2)
[(x+y)²-(x+y)(x-y)]÷(-2-y)
= [(x² +2xy +y²) -(x² -y²)] ÷ [-(y+2)]
= -[2y² +2xy] ÷ (y+2)
= -(2y² +2xy)/(y+2)
=2xy/-y-2

2. 分解因式
-2x³+8xy²
= -2x(x² -4y²)
= -2x(x+2y)(x-2y)

3.已知x²-2x=2，求代数式（x-1）²+（x+3）（x-3）+（x-3）（x-1）的值

（x-1）²+(x+3)(x-3）+(x-3)(x-1)
= (x² -2x +1) +(x² -9) +(x² -4x +3)
= 3x² -6x -5
= 3(x² -2) -5
当x²-2x=2时
原式
= 3*2 -5
= 1.

1. 化简
（1）
(2a+1)(-a-2)+a(2-a)
= (-2a² -5a -2) +(2a -a²)
= -3a² -3a -2

(2)
[(x+y)²-(x+y)(x-y)]÷(-2-y)
= [(x² +2xy +y²) -(x² -y²)] ÷ [-(y+2)]
= -[2y² +2xy] ÷ (y+2)
= -(2y² +2xy)/(y+2)

2. 分解因式
-2x&#