UC知道一元二次方程配方法 20道题全对奖励3QB 要步骤哦 每对5道题以上0.5QB
来源：百度知道 编辑：UC知道 时间：2024/05/24 06:30:34
[1] x^2-2X-2=0
[2] 2x^2+3X-1=0
[3]2x^2-4系＋1＝0
[4]x^2+6X+3=0
[5]x^2-2√7X+2=0
[6][X+2]+4X=0
[7]-3x^2-6X+1=0
[8]2/3y^2+1/3Y-2=0
[9]0.4x^2-0.8X-1=0
[10]x^2+7X-3=0
[11][X-1]^2-2[X-1]+1/2=0
[12]x^2+X-1=0
[13]2x^2-3X-6=0
[14][3X-1]^2=[3-2X]^2
[15][X-5][X+3]+[X-2][X+4]=26
[16][2X-3][2X-3]=x^2-6X+9
[17]4[X-1]^2-9=0
[18]x^2-2√5X+2=0
[19][Y-3]^2-18=0
[20][Y+√3]^2=4√3Y
题目很简单的啊
[2] 2x^2+3X-1=0
[3]2x^2-4系＋1＝0
[4]x^2+6X+3=0
[5]x^2-2√7X+2=0
[6][X+2]+4X=0
[7]-3x^2-6X+1=0
[8]2/3y^2+1/3Y-2=0
[9]0.4x^2-0.8X-1=0
[10]x^2+7X-3=0
[11][X-1]^2-2[X-1]+1/2=0
[12]x^2+X-1=0
[13]2x^2-3X-6=0
[14][3X-1]^2=[3-2X]^2
[15][X-5][X+3]+[X-2][X+4]=26
[16][2X-3][2X-3]=x^2-6X+9
[17]4[X-1]^2-9=0
[18]x^2-2√5X+2=0
[19][Y-3]^2-18=0
[20][Y+√3]^2=4√3Y
题目很简单的啊
简单自己干嘛不做~~~~~~
(1)X^2-2X+1=3, (X-1)^2=3
(2)2X^2+3X+9/8=1/8 (√2X+9/2√2)^2=1/8
(3)2X^2-4X+2=1 (√2X-√2)^2=1
(4)X^2+6X+9=6 (X+3)^2=6
(5)X^2-2√7X+7=5 (X-√7)^2=5
(6)(X+2)^2+4X=0 X^2+4X+4+4X=0 X^2+8X+16=12 (X+4)^2=12
(7)3X^2+6X-1=0 3X^2+6X+3=4 (√3X+√3)^2=4
(8)2Y^2+Y-6=0 2Y^2+Y+1/8=49/8 (√2Y+1/2√2)^2=49/8
(9)2X^2-4X-5=0 2X^2-4X+2=7 (√2X-√2)^2=7
(10)X^2+7X+49/4=61/4 (X+7/2)^2=61/4