已知1/x-1/y=3,求(2y-3xy-2x) / (y+2xy-x)的值

来源:百度知道 编辑:UC知道 时间:2024/05/14 03:05:04
急!!!!!!!!!!!!!!!!!
为什么y-x=3xy ?????????????????????????????????????????????????????????????????????????????过程详细一点!!!!!!!!!!!

看似复杂,其实不难。
因为1/x-1/y=(y-x)/xy=3,
所以(y-x)=3xy
(2y-3xy-2x) / (y+2xy-x)
=〔2(y-x)-3xy〕/[(y-x)+2xy]
= [2*3xy-3xy]/[3xy+2xy]
= 3xy/5xy
= 3/5

1/x-1/y=3,
y-x=3xy
(2y-3xy-2x) / (y+2xy-x)
=[2y-2x-(y-x)] / [y+2/3(y-x)-x]
=(y-x)/(5/3(y-x)
=3/5

原式分子,分母同除以xy,得(2/x-3-2/y)/(1/x+2-1/y)=(-3+2×3)/(2+3)=3/5
符号刚才弄错了