求函数的导数

Y=x^n导数为n*x^(n-1)
你没学过数学，还是没事玩呢，晕．．．

1 (2/3)x^(-1/3)
2 y=((1'*x^1/3)-1*(x^1/3))/(x^1/9)
然后自己会算了吧
3 y=x^(2+3/7)=(17/7)x^(8/7)

y'=2/3x^(-1/3)
y'=-1/3(x^-4/3)

y'=17/7x^(10/7)

y=x^(2/3)
y'=2[x^(-1/3)]/3

y=1/x^(1/3)=x^(-1/3)
y'=-[x^(-4/3)]/3

y=x^2•x^(3/7)=x^(17/7)
y'=17x^[(10/7)]/7

y'=1/x-(2xsinx-x^2*cosx)/(sinx)^2