a☆b=(b-a)/(a*b)则1☆2-2☆3-……2006☆2007-2007☆2008

来源:百度知道 编辑:UC知道 时间:2024/06/07 03:25:20
快,有急用!

a*b=(b-a)/ab
=1/a-1/b
1*2-2*3-3*4-.......-2006*2007-2007*2008
=1-1/2-1/2+1/3-1/3+1/4-......-1/2006+1/2007-1/2007+1/2008
=1-1+1/2008(消掉共同项)
=1/2008
a☆b=(b-a)/(a*b)=1/a-1/b
所以原式=(1/1-1/2)-(1/2-1/3)-(1/3-1/4)-……-(1/2006-1/2007)-(1/2007-1/2008)=1/2008

a☆b=(b-a)/(a*b)=1/a-1/b
1☆2-2☆3-……2006☆2007-2007☆2008
=1/1-1/2+1/2-1/3+1/3-1/4+……+1/2007-1/2008(中间全部消掉)
=1-1/2008
=2007/2008

a☆b=(b-a)/(a*b)=1/a-1/b
所以原式=(1/1-1/2)-(1/2-1/3)-(1/3-1/4)-……-(1/2006-1/2007)-(1/2007-1/2008)=1/2008

a*b=(b-a)/ab
=1/a-1/b
1*2-2*3-3*4-.......-2006*2007-2007*2008
=1-1/2-1/2+1/3-1/3+1/4-......-1/2006+1/2007-1/2007+1/2008
=1-1+1/2008(消掉共同项)
=1/2008