cos2x=cosx+sinx在[-2π,2π]的解集是

cos2x=cosx+sinx
两边平方
(cos2x)^2=(sinx+cosx)^2
(cos2x)^2=(sinx)^2+(cosx)^2+2sinxcosx
1-(sin2x)^2=1+sin2x
(sin2x)^2+sin2x=0
sin2x(sin2x+1)=0
sin2x=0时 2x=2kπ x=kπ 取k=-2,-1,0,1,2 x=-2π,-π,0,π,2π
sin2x=-1时 2x=3π/2+2kπ x=3π/4+kπ 取k=-2,-1,0,1 x=-5π/4,-π/4,3π/4,7π/4
k是整数