很简单的因式分解问题

来源:百度知道 编辑:UC知道 时间:2024/06/04 18:27:10
6(p+q)^-2(p+q)
2(x-y)^-x(x-y)
m(a-b)-n(b-a)
121*0.13+12.1*0.9-1.2*12.1
2.34*13.2+0.66*13.2-26.4
对不起是2次方

(1)原式=2(p+q)(3p+3q-1)
(2)原式=(x-y)(2x-2y-x)=(x-y)(x-2y)
(3)原式=(a-b)(m+n)
(4)原式=12.1×(1.3+0.9-1.2)=12.1
(5)原式=13.2×(2.34+0.66-2)=13.2

这些题应该很简单,好好学习,天天向上。
祝你学业有成!(*^__^*)

6(p+q)^2-2(p+q)=2(p+q)(3p+3q-1)
2(x-y)^2-x(x-y)=(x-y)(2x-2y-x)
=(x-y)(x-2y)
m(a-b)-n(a-b)=(a-b)(m-n)
121*0.13+12.1*0.9-1.2*12.1
=12.1*10*0.13+12.1*0.9-1.2*12.1
=12.1(10*0.13+0.9-1.2)
=12.1(1.3+0.9-1.2)
=12.1*1=12.1
2.34*13.2+0.66*13.2-26.4
=2.34*13.2+0.66*13.2-2*13.2
=13.2(2.34+0.66-2)
=13.2*1
=13.2

6(p+q)^-2(p+q)=2(p+q)(3p+3q-1)
2(x-y)^-x(x-y))=(x-y)(2x-2y-x)=(x-y)(x-2y)
m(a-b)-n(b-a) =m(a-b)-n(a-b)=(a-b)(m-n)
121*0.13+12.1*0.9-1.2*12.1 =12.1*(1.3+0.9-1.2)=12.1
2.34*13.2+0.66*13.2-26.4=13.2*(2.34+0.66-2)=13.2