3/1x+10=x-5/1
来源:百度知道 编辑:UC知道 时间:2024/06/23 20:48:15
帮帮忙!!
已知x*x-3x+1=0,求x*x+1/x*x
(X-1/X)=5,且X<0,求x^10+x^6+x^4+1除以x^10+x^8+x^2+1的值
(x-4)(x-2)-(x-1)(x+3),其中x=-2/5
(x+1)(x-4)-6=x^2-3x-4-6=x^2-3x-10=(x+2)(x-5)中x^2-3x-10怎么弄成(x-5)(x+2).
(5/(X-1)(X+2))+(3/(X+2)(X+3))=2/(X-1)(X-3)
x+1/x=3,求(x^10+x^8+x^2+1)/(x^10+x^6+x^4+1)的值
(x+2/x+1)+ (x+6/x+5)=(x+3/x+2)+(x+5/x+4)怎么解?
方程(x+1/x+2)+(x+2/x+3)=(x+3/x+4)+(x+4/x+5)的解
x+2/x+1-x+3/x+2=x+4/x+3-x+5/x+4
x^2-3x+1=0,求2x^5-5x^4-x^3+x^2-6x/x^2+1