1+1/2+2/2+1/2+1/3+2/3+3/3+2/3+1/3+......1/100+2/100+100/100+99/100+......1/100=?
来源:百度知道 编辑:UC知道 时间:2024/06/05 15:35:32
小学奥数解答
1+1/2+2/2+1/2+1/3+2/3+3/3+2/3+1/3+......1/100+2/100+100/100+99/100+......1/100
=1+(1+2)/2+(1+2+3)/3+(1+2+3+4)/4+.....(1+2+3+4+...98+99)/99+(1+2+3+4+....99+100)/100
再进一步转化(这步很关键,消去异分母)
1+(1+2)/2+(1+3)/2+(1+4)/2+........(1+99)/2+(1+100)/2
我们最后把1分成(1+1)/2就很容易解得出来了(就是100个1与1至100的连加其和再除以2)
(100+5050)/2=2575
1/n+2/n+3/n+……+n/n
=[n(n+1)/2]/n
=(n+1)/2
=n/2+1/2
所以原式=(1/2+1/2)+(2/2+1/2)+(3/2+1/2)+……+(100/2+1/2)
=(1+2+3+……+100)/2+100*(1/2)
=(100*101/2)/2+50
=2525+50
=2575
1/100+2/100+100/100+99/100+......1/100=100*(100+1)/100*2
每一个同分母n的和为(n+1)/2
所以整个式子等于【(n+1)(n+2)/2】/2
=(n+1)(n+2)/4,n=100
式子和为101*102/2=2575.5
2575
1/2-1/2=?
3/2=2+1/1*2=1/1+1/2
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)
(1-1/2^2)*(1-1/3^2)*(1-1/4^2).......(1-1/100^2)
1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100)
1+1/(1+2)+1/(1+2+3)+-------+1/(1+2+3+----+100)
1+1/1+2+1/1+2+3+...+1/1+2+3...+2000
1+1/1+2+1/1+2+3.........+1/1+2+3.....100
1*(1/1+2)*(1/1+2+3)*~~~*(1/1+2+~~~2005)=?
1+1/2+1/3+.....+1/n