求(x-y+x-y/4xy)(x+y-x+y/4xy)的详细解说答案

上面的回答都不对啊！y/4xy不是y/(4xy)!!
(x-y+x-y/4xy)(x+y-x+y/4xy)
=(2x-y-xy^2/4)(y+xy^2/4)
=2xy+(xy)^2/2-y^2-(xy^3)/2-(x^2y^4)/16

=(2x-y-y/4xy)(y+y/4xy)
=(2x-y-1/4x)(y+1/4x)
=[2x-(y+1/4x)](y+1/4x)
=2xy+1/2-(y+1/4x)的平方
=2xy+1/2-y-1/16x的平方-y/2x

(x-y+x-y/4xy)(x+y-x+y/4xy)
=(2x-y-1/4x)(y+1/4x)
=2xy+1/2-y*y-y/4x-y/4x-1/(16*x*x)
=2xy+1/2-y*y-y/2x-1/(16*x*x)

(x-(y-x+y/4xy))((x+(y-x+y/4xy))=x*x-(y-x+y/4xy)(y-x+y/4xy)

用分配率？？？