1/(1×2)+1/(2×3)+....1/(99×100)的值
来源:百度知道 编辑:UC知道 时间:2024/06/16 14:34:00
不知道大家看得懂吗?!是分数形式...
您好!
因为1/2=1-1/2
1/6=1/2-1/3
1/12=1/3-1/4
依此类推,原式就=
1-1/2+1/2-1/3+1/3-1/4......+1/99-1/100=
1-1/100=99/100
原式=1-(1\1乘以100)
1/2*[(2-1)/1*2+(3-2)/2*3+....+(100-99)/100*99]=1/2*(1-1/100)=99/200
1/(1×2)+1/(2×3)+....1/(99×100)=
(2-1)/(1×2)+(3-2)/(3×2)....(100-99)/(99×100)=
2/(1×2)-1/(1×2)+3/(3×2)-2/(3×2)....100/(99×100)-99/(99×100)=1-1/100=99/100
原式=1-2/1+2/1-3/1+……99/1-100/1
=1-100/1
=100分之99
(1/2005-1)(1/2004-1)........(1/3-1)(1/2-1)
1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100)
1+1/(1+2)+1/(1+2+3)+-------+1/(1+2+3+----+100)
1+1/1+2+1/1+2+3+...+1/1+2+3...+2000
1+1/1+2+1/1+2+3.........+1/1+2+3.....100
1*(1/1+2)*(1/1+2+3)*~~~*(1/1+2+~~~2005)=?
(1-1/2)(1-1/3)(1-1/4)(1-1/5).....(1-1/1000)
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)
(1-1/2^2)*(1-1/3^2)*(1-1/4^2).......(1-1/100^2)
1+1/2+1+1/3+1+1/4+......+1/100=?