1+1/1+2+1/1+2+3+1/1+2+3+4+...+1/1+2+3+...+99+100

来源：百度知道编辑：UC知道时间：2024/06/24 19:00:38

这道简算麻烦大家想想，过程要详细，拜托了

1+1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+……+1/(1+2+3+……+100)
=1+2/[(1+2)*2]+2/[(1+3)*3]+2/[(1+4)*4]+……+2/[(1+100)*100]
=1+2*[(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+(1/5-1/6)+……+(1/99-1/100)]
=1+2*(1/2-1/100)
=1+49/50
=99/50

1+1/1+2+1/1+2+3+1/1+2+3+4+1/1+2+3+4+5+.......+1/+2+3+.....+100
=(1+2+3+4+5+.....+100)+99×(1/1)
=(1+100)×[(100-1)/1+1]+99
=101×50+99
=5050+99
=5149

1+2+3+4+...+1 ...是什么啊是3+2 还是啥啊
楼上的，看好题目啊

一楼的满意回答是错误的啊怎么又那么多的人竖大拇指啊真是想不通啊

(1/2005-1)(1/2004-1)........(1/3-1)(1/2-1) 1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100) 1+1/(1+2)+1/(1+2+3)+-------+1/(1+2+3+----+100) 1+1/1+2+1/1+2+3+...+1/1+2+3...+2000 1+1/1+2+1/1+2+3.........+1/1+2+3.....100 1*(1/1+2)*(1/1+2+3)*~~~*(1/1+2+~~~2005)=? (1-1/2)(1-1/3)(1-1/4)(1-1/5).....(1-1/1000) 1+1/2+1+1/3+1+1/4+......+1/100=? (1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8) (1-1/2^2)*(1-1/3^2)*(1-1/4^2).......(1-1/100^2)