因式分解：（初二的）

来源：百度知道 编辑：UC知道 时间：2024/05/05 10:18:56
(1) x²+2x-3=
(2) x²-7x-8=
(3) x²-8x+12=
(4) x²+9x+18=
(5)(x+1)(x+2)(x+3)(x+4)+1=

1) x²+2x-3=(x-1)*(x+3)
(2) x²-7x-8=(x+1)*(x-8)
(3) x²-8x+12=(x-2)*(x-6)
(4) x²+9x+18= (x+3)*(x+6)
(5)(x+1)(x+2)(x+3)(x+4)+1=(x²+5x+4)(x²+5x+6)+1 =(x²+5x)^2+10(x²+5x)+25 =(x²+5x+5)^2

(1) x²+2x-3= (x-1)(x-3)
(2) x²-7x-8= (x-8)(x+1)
(3) x²-8x+12= (x-2)(x-6)
(4) x²+9x+18= (x+3)(x+6)
(5)(x+1)(x+2)(x+3)(x+4)+1==(x^2+5x+4)(x^2+5x+6)+1 =(x^2+5x)^2+10(x^2+5x)+25 =(x^2+5x+5)^2

(1) x²+2x-3= (x-1)(x-3)
(2) x²-7x-8= (x-8)(x+1)
(3) x²-8x+12= (x-2)(x-6)
(4) x²+9x+18= (x+3)(x+6)
(5)(x+1)(x+2)(x+3)(x+4)+1==(x^2+5x+4)(x^2+5x+6)+1 =(x^2+5x)^2+10(x^2+5x)+25 =(x^2+5x+5)^2

我级别低，选我吧~~~我在这！

一样的啊