隐函数求导怎么求呀

对x求导
(e^y)', 此处y是x的函数
所以=e^y*y'

(xy)'=x'*y+x*y'=y+x*y'

e'=0
所以e^y*y'+y+x*y'=0
(e^y+x)*y'+y=0
y'=-y/(e^y+x)

e^y+xy-e=0

d(e^y) + d(xy) - d(e) = 0

e^y dy + xdy + ydx = 0

(e^y + x)dy = -ydx

dy/dx = -y/(e^y + x)

把y看成x的函数，两边求导，的e^y.y'+y+xy'=0可得y'=-y/e^y+x