初三 数学 死难解的方程 请详细解答,谢谢! (7 10:43:1)

2x/(x+1)-5x/(x-1)=-6

[2x(x-1)-5x(x+1)]/(x+1)(x-1)=-6
(2x^2-2x-5x^2-5x)/(x^2-1)=-6
(-3x^2-7x)/(x^2-1)+6=0
(-3x^2-7x+6x^2-6)/(x^2-1)=0
(3x^2-7x-6)/(x^2-1)=0
(3x+2)(x-3)/(x^2-1)=0
x=-2/3 或 x=3

晕~我理解错误

X+1分之2X-X-1分之5X=-6
2x(x-1)-5x(x+1)=-6(x+1)(x-1)
2x*2-2x-5x*2-5x=-6x*2+6
-3x*2-7x+6x*2-6=0
3x*2-7x-6=0
(3x+2)(x-3)=0
x1=-2/3,x2=3

{注}：x*2，x的平方~~！