1/(1*3)+1/(3*5)+1/(5*7)……+1/(2001*2003)

来源:百度知道 编辑:UC知道 时间:2024/06/22 21:14:02
用简便方法计算.

拆项
1/(3*5)=1/2*(1/3-1/5).....
最后的结果是
1/2*(1/3-1/2003)=...自己算一下

1/2(1/1-1/3+1/3-1/5+.....+1/2001-1/2003)=1/2(1-1/2003}=1001/2003

1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+.....+(1/2001-1/2003)]
=1/2[1-1/2003]=1001/2003

告诉你解题思路
1/(1*3)+1/(3*5)+1/(5*7)……+1/(2001*2003)
=〔2/(1*3)+2/(3*5)+2/(5*7)……+2/(2001*2003)〕/2
=〔(1/1-1/3)+(1/3-1/5)+……(1/2001-1/2003)〕/2
=(1/1-1/3+1/3-1/5+……+1/2001-1/2003)/2
=(1/1-1/2003)/2
=2002/2003/2
=1001/2003

=1/2*[(1/1-1/3)+(1/3-1/5)+(1/5-1/7)+……+(1/2001-1/2003)]
=1/2*[1-1/2003]
=1/2*(2002/2003)
=1001/2003

1/(1*3)+1/(3*5)+1/(5*7)……+1/(2001*2003)
=〔2/(1*3)+2/(3*5)+2/(5*7)……+2/(2001*2003)〕/2
=〔(1/1-1/3)+(1/3-1/5)+……(1/2001-1/2003)〕/2
=(1/1-1/3+1/3-1/5+……+1/2001-1/2003)/2
=(1/1-1/2003)/2
=2002/2003/2
=1001/2003