1/(1*3)+1/(3*5)+1/(5*7)……+1/(2001*2003)
来源:百度知道 编辑:UC知道 时间:2024/06/22 21:14:02
用简便方法计算.
拆项
1/(3*5)=1/2*(1/3-1/5).....
最后的结果是
1/2*(1/3-1/2003)=...自己算一下
1/2(1/1-1/3+1/3-1/5+.....+1/2001-1/2003)=1/2(1-1/2003}=1001/2003
1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+.....+(1/2001-1/2003)]
=1/2[1-1/2003]=1001/2003
告诉你解题思路
1/(1*3)+1/(3*5)+1/(5*7)……+1/(2001*2003)
=〔2/(1*3)+2/(3*5)+2/(5*7)……+2/(2001*2003)〕/2
=〔(1/1-1/3)+(1/3-1/5)+……(1/2001-1/2003)〕/2
=(1/1-1/3+1/3-1/5+……+1/2001-1/2003)/2
=(1/1-1/2003)/2
=2002/2003/2
=1001/2003
=1/2*[(1/1-1/3)+(1/3-1/5)+(1/5-1/7)+……+(1/2001-1/2003)]
=1/2*[1-1/2003]
=1/2*(2002/2003)
=1001/2003
1/(1*3)+1/(3*5)+1/(5*7)……+1/(2001*2003)
=〔2/(1*3)+2/(3*5)+2/(5*7)……+2/(2001*2003)〕/2
=〔(1/1-1/3)+(1/3-1/5)+……(1/2001-1/2003)〕/2
=(1/1-1/3+1/3-1/5+……+1/2001-1/2003)/2
=(1/1-1/2003)/2
=2002/2003/2
=1001/2003
(1/2005-1)(1/2004-1)........(1/3-1)(1/2-1)
(1-1/100)(1-1/99)(1-1/98)......(1-1/3
(1-1/2)(1-1/3)(1-1/4)(1-1/5).....(1-1/1000)
1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100)
1+1/(1+2)+1/(1+2+3)+-------+1/(1+2+3+----+100)
1+1/2+1+1/3+1+1/4+......+1/100=?
1+1/2+1/3+.....+1/n
1+1/2+1/3+...+1/100
1+1/3+1/6+........+1/55
1-1/2+1/3-.....-1/10