a,b属于正实数,a+b=1,求证1/a+1/b+1/ab>=8

来源:百度知道 编辑:UC知道 时间:2024/05/17 12:16:02
还有(a+1/a)^2+(b+1/b)^2>=25/2

1/a+1/b+1/ab
=1/a+1/b+(a+b)/ab
=1/a+1/b+(1/b+1/a)
=2(1/a+1/b)
=2[(a+b)/a+(a+b)/b)]
=2[1+b/a+a/b+1]
=2[2+(b/a+a/b)]
≥2[2+2]
=2*4
=8
1/a+1/b+1/ab>=8

a^2+b^2≥(a+b)^2/2=1/2
ab≤[(a+b)/2]^2=1/4
1/ab≥4
1/a^2+1/b^2≥2/ab≥2*4=8

(a+1/a)^2+(b+1/b)^2
=a^2+1/a^2+2+b^2+1/b^2+2
=4+(a^2+b^2)+(1/a^2+1/b^2)
≥4+1/2+8
=25/2

设a=sin(x)^2
b=cos(x)^2
1/a+1/b+1/(ab)=2/(sin^2*cos^2);sincos<=0.5;1/a+1/b+1/ab>=8
a+1/a)^2+(b+1/b)^2=4+sin^4+cos^4+1/sin^4+1/cos^4>=4+2sin^2+cos^2+2/(sin^2*cos^2)
由于sin^2cos^2<=0.25
所以当sin^2cos^2=0.25时4+2sin^2+cos^2+2/(sin^2*cos^2)取最小,即sin^2=cos^2=0.5此时4+2sin^2+cos^2+2/(sin^2*cos^2)=25/2
注:
x+1/x的单调性:
f(x)=x+1/x
f'=1-1/x^2当 -1<x<1时f(x)单调增加
所以sin^2cos^2+1/(sin^2*cos^2)当sin^2*cos^2取最大值0.25时最大

1, 1/a+1/b=(a+b)/ab=1/ab
1/a+1/b+1/ab=2/ab
1=a+b>=2根号(ab) 根号(ab) <=1/2